Filter list by another list python
WebSep 13, 2024 · list1 = ['Python', 'Java', 'JavaScript'] list2 = ['JavaScript is client-side scripting language', 'PHP is a server-side scripting language', 'Java is a programming language', 'Bash is a scripting language'] # Filter the second list based on first list filter_data = [x for x in list2 if all(y not in x for y in list1)] # Print filter list print ... WebJun 3, 2024 · It can be as simple as this, using list comprehension: >>> lst = [x for x in listB for a in listA if a in x] >>> lst ['sentence 2 contains cat', 'sentence 6 contains dog'] Edit: …
Filter list by another list python
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WebNov 2, 2024 · You can create a boolean list depending upon the value you want to keep in list A and then filter the lists based on this new Boolean list. lstA = ['good','good2', ''] lstB = [1,2,3] filter_list= [element!='' for element in lstA] In this case the filter_list will have values like [True, True, False]. WebJun 9, 2013 · 1. Check out filter and any in the python docs. >>> data_list = ['a.1','b.2','c.3'] >>> test_list = ['a.','c.'] >>> new_list = filter (lambda x: any (x.startswith (t) for t in test_list), data_list) >>> new_list ['a.1', 'c.3'] Then you can do whatever you want with the stuff in your new_list. As @Chepner points out, you can also supply a tuple ...
WebMay 30, 2024 · filtered_list = [i for (i, v) in zip (list_a, filter) if v] Using zip is the pythonic way to iterate over multiple sequences in parallel, without needing any indexing. This assumes both sequences have the same length (zip stops after the shortest runs out). Using itertools for such a simple case is a bit overkill ... WebApr 17, 2024 · The filter(function, iterable) function takes a function as input that takes on argument (a list element) and returns a Boolean value that …
Web1 Answer. Sorted by: 65. Use list comprehension, divisibleBySeven = [num for num in inputList if num != 0 and num % 7 == 0] or you can use the meetsCondition also, divisibleBySeven = [num for num in inputList if meetsCondition (num)] you can actually write the same condition with Python's truthy semantics, like this. WebJan 28, 2010 · Another way is to use the filter function. In Python 2: >>> filter (lambda k: 'ab' in k, lst) ['ab', 'abc'] In Python 3, it returns an iterator instead of a list, but you can cast it: >>> list (filter (lambda k: 'ab' in k, lst)) ['ab', 'abc'] Though it's better practice to use a comprehension. Share Improve this answer Follow
WebPython’s filter () is a built-in function that allows you to process an iterable and extract those items that satisfy a given condition. This process is commonly known as a filtering operation. With filter (), you can apply a filtering function to an iterable and produce a new iterable with the items that satisfy the condition at hand.
WebAug 5, 2024 · Since you specifically asked about filtering the list you have, you can use filter builtin with lambda to filter out the elements from the list. >>> list (filter (lambda x: x.get ('text', '')=='abc', listpost)) [ {'post_id': '01', 'text': 'abc', 'time': datetime.datetime (2024, 8, 5, 15, 53, 19), 'type': 'normal'}] s j birkhall sheffieldWeb22 hours ago · 0. This must be a obvious one for many. But I am trying to understand how python matches a filter that is a series object passed to filter in dataframe. For eg: df is a dataframe. mask = df [column1].str.isdigit () == False ## mask is a series object with boolean values. when I do the below, are the indexes of the series (mask) matched with ... sutherland\u0027s petworksWebI need to compare two lists in order to create a new list of specific elements found in one list but not in the other. For example: main_list= [] list_1= ["a", "b", "c", "d", "e"] list_2= ["a", "f", "c", "m"] I want to loop through list_1 and append to main_list all the elements from list_2 that are not found in list_1. The result should be: sutherland\u0027s lawtonWebApr 23, 2012 · As you see the operation of masking on array is more elegant compared to list. If you try to use the array masking scheme on list you'll get an error: >>> lst [msk] Traceback (most recent call last): File "", line 1, in TypeError: only integer arrays with one element can be converted to an index. sjbkathleticsWebAug 26, 2013 · i'm trying to filter a list, i want to extract from a list A (is a list of lists), the elements what matches they key index 0, with another list B what has a serie of values s j b institute of technology kengeriWebMar 14, 2015 · 1. Universal approach to filter the list of dictionaries based on key-value pairs. def get_dic_filter_func (**kwargs): """Func to be used for map/filter function, returned func will take dict values from kwargs keys and compare resulted dict with kwargs""" def func (dic): dic_to_compare = {k: v for k, v in dic.items () if k in kwargs} return ... sjb lawn care \\u0026 landscaping llcWebJun 22, 2012 · answered Jun 21, 2012 at 20:32. DSM. 336k 63 585 487. Add a comment. 6. I would use itertools.compress () along with a generator expression to do this: def func (a, b, c): return itertools.compress (a, (x == c for x in b)) Note that this will return a generator. If you need a list, wrap it in a list () call. sjb learning commons